Paper 1 · Complex Numbers
⏱ Tested in 1 exam question since 2025
Lesson 17 of 17
Complex Numbers 17 – Proof of Sin(3A) and Cos(3A)
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- Prove cos 3θ = 4cos³θ − 3cos θ and sin 3θ = 3sin θ − 4sin³θ using De Moivre
- Expand (cos θ + i sin θ)³ and group the real and imaginary parts
- Equate real or imaginary parts on both sides to isolate each identity
- Use sin²θ + cos²θ = 1 to finish each proof in a single trig function
Most recent exam questions
- 2025 P1 Q4(b)
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